(1/4)^2=x

Solution for (1/4)^2=x equation:

(1/4)^2=x

We move all terms to the left:

(1/4)^2-(x)=0

We add all the numbers together, and all the variables

-x+(+1/4)^2=0

We add all the numbers together, and all the variables

-1x+(+1/4)^2=0

We multiply all the terms by the denominator


-1x*4)^2+(+1=0

Wy multiply elements

-4x^2+1=0

a = -4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-4)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-4}=\frac{-4}{-8}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-4}=\frac{4}{-8}
=-1/2
$